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4x^2=0.125
We move all terms to the left:
4x^2-(0.125)=0
We add all the numbers together, and all the variables
4x^2-0.125=0
a = 4; b = 0; c = -0.125;
Δ = b2-4ac
Δ = 02-4·4·(-0.125)
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2}}{2*4}=\frac{0-\sqrt{2}}{8} =-\frac{\sqrt{}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2}}{2*4}=\frac{0+\sqrt{2}}{8} =\frac{\sqrt{}}{8} $
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